Quentin Halys / Pierre-Hugues Herbert vs Fernando Romboli / John-Patrick Smith · ATP
Quentin Halys / Pierre-Hugues Herbert
France
2 – 1
Final
Times in UTC until your browser converts them.
Fernando Romboli / John-Patrick Smith(4)
Brazil
Metz, France
At the Moselle Open, Quentin Halys / Pierre-Hugues Herbert beat Fernando Romboli / John-Patrick Smith 4-6 6-2 1-0 in the Round 1.
Overview
- Starts
- Event
- ATP
- Tournament
- Moselle Open
- Draw
- Men's Doubles
- Round
- Round 1
- Court
- Court 1
- Ground
- Metz, France
Set scores
| Player | 1 | 2 | 3 | Total |
|---|---|---|---|---|
 Quentin Halys / Pierre-Hugues Herbert | 4 | 6 | 110 | 2 |
 Fernando Romboli / John-Patrick Smith(4) | 6 | 2 | 04 | 1 |
Quentin Halys (FRA) & Pierre-Hugues Herbert (FRA) bt (4) Fernando Romboli (BRA) & John-Patrick Smith (AUS) 4-6 6-2 1-0 (10-4)
